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x + 2x + 3x + ...+ 9x = 1800
x(1+2+3+...+9)=1800
45x=1800
x=1800:45
x=40
Vậy, x=40
\(x+2x+3x+....+9x=990.\)
\(\Rightarrow x.\left(1+2+3+....+9\right)=990\)
\(\Rightarrow x.45=990\)
\(\Rightarrow x=990:45\)
\(\Rightarrow x=22\)
X duoc xuat hien so lan la:
1+2+3+4+5+6+7+8+9=45
x=990÷45=22
ĐS:22
x+2x+3x+...+9x=4593
x(1+2+3+...+9)=4593
x.45=4593
x=4593:45
x=102,666667
Ta có;
x+2x+3x+4x+...+9x=1000-100
=>x+2x+3x+4x+...+9x=900
=>(1+2+3+4+....+9)x=900
=>[(1+9).9:2]x=900
=>45x=900
x=900:45=20
cho tớ đúng nha
Ta có;
x+2x+3x+4x+...+9x=1000-100
=>x+2x+3x+4x+...+9x=900
=>(1+2+3+4+....+9)x=900
=>45x=900
x=900:45=20
x+ 2x + 3x +...+ 9x = 459 -\(3^2\)
x+ 2x + 3x +...+ 9x =459 -9
x+ 2x + 3x +...+ 9x =450
x.(1+2+3+...+9) = 450
x. 45 = 450
x = 450 : 45
x = 10
HT!!!
a)
<=> 3x - 3 + x - 2 = 2x - 2 - x + 1
<=> 3x + x - 2x + x = -2 + 1 + 3 + 2
<=> 3x = 4
<=> x = 4/3
Các câu sau làm tương tự
\(\left(3x-3\right)+\left(x-2\right)=\left(2x-2\right)-\left(x-1\right)\)
<=> \(3x-3+x-2=2x-2-x+1\)
<=> \(4x-5=x-1\)
<=> \(3x=4\)
<=> \(x=\frac{4}{3}\)
Vậy....
264+12x=1800
12x=1536
x=128
(x+73):19=321
x+73=6099
x=6026
2x+3x+4x=18
9x=18
x=2
10<2x<20
=>5<x<10
x=6,7,8,9
\(264+12x=1800\)
\(\Leftrightarrow12x=1536\)
\(\Leftrightarrow x=128\)
==============
\(\left(x+73\right):19=321\)
\(\Leftrightarrow x+73=6099\)
\(\Leftrightarrow x=6026\)
===============
\(2x+3x+4x=18\)
\(\Leftrightarrow x.\left(2+3+4\right)=18\)
\(\Leftrightarrow x.9=18\)
\(\Leftrightarrow x=2\)
================
\(10< 2x< 20\)
..................................
\(2x=12\Leftrightarrow x=6\)
\(2x=14\Leftrightarrow x=7\)
\(2x=16\Leftrightarrow x=8\)
\(2x=18\Leftrightarrow x=9\)
\(x\in\left\{6;7;8;9\right\}\)
12x = 1800 - 264
12x = 1536
x = 1536 : 12
x = 128
( x + 73 ) : 19 = 321
( x + 73 ) = 321 x 19
x + 73 = 6099
x = 6099 - 73
x = 6026
2x + 3x + 4x = 18
x . ( 2 + 3 + 4 ) = 18
x . 9 = 18
x = 18 : 9
x = 2
10 < 2x < 20
x = 6 ; 7 ; 8 ; 9
Rút x ta có: x.(1+2+3+...+9)=1800
x.45=1800
x=1800/45=40