X*(1+2+3+4+5+6+7+8+9+10)=-165

X*55=-165

X=-165/55=-3

111111111111111111111111111111111111111111111111111111111111111111111111111111111111111

(1x + 9x) + (2x + 8x) + (3x + 7x) + (4x + 6x) + 5x + 10x = -165

10x^6 + 5x = -165

= 65x (-165)

= -100

x+2x+3x+...+9x=4593

x(1+2+3+...+9)=4593

x.45=4593

x=4593:45

x=102,666667

ai diễn giải ra cho ****

x + 2x + 3x + ...+ 9x = 1800

x(1+2+3+...+9)=1800

45x=1800

x=1800:45

x=40

Vậy, x=40

Ta có:

\(x+2x+3x+...+9x=1800\)

\(45x=1800\)

\(x=\frac{1800}{45}=40\)

a) 

<=> 3x - 3 + x - 2 = 2x - 2 - x + 1

<=> 3x + x - 2x + x = -2 + 1 + 3 + 2

<=>    3x               = 4

<=>   x                  = 4/3

Các câu sau làm tương tự

\(\left(3x-3\right)+\left(x-2\right)=\left(2x-2\right)-\left(x-1\right)\)

<=>   \(3x-3+x-2=2x-2-x+1\)

<=>  \(4x-5=x-1\)

<=> \(3x=4\)

<=>  \(x=\frac{4}{3}\)

Vậy....

a) ( 2x - 3 ) - ( x - 5 ) = ( x + 7 ) - ( x + 2 ) 

<=> 2x - 3 - x + 5 = x + 7 - x - 2

<=> x = 3

b)(7x-5)-(6x+4)=(2x+3)-(2x+1)

<=> 7x - 5 - 6x - 4 = 2x + 3 - 2x - 1

<=> x = 11

c)(9x-3)-(8x+5)=(3x+2)

<=> 9x - 3 - 8x - 5 = 3x + 2

<=> -2x = 10

<=> x = -5

d)(x+7)-(2x+3)=(3x+5)-(2x+4)

<=> x + 7 - 2x - 3 = 3x + 5 - 2x - 4

<=> -2x = -3

<=> x = 3/2

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Rút x ta có: x.(1+2+3+...+9)=1800

                 x.45=1800

                  x=1800/45=40

Ta có;

x+2x+3x+4x+...+9x=1000-100

=>x+2x+3x+4x+...+9x=900

=>(1+2+3+4+....+9)x=900

=>[(1+9).9:2]x=900

=>45x=900

x=900:45=20

cho tớ đúng nha

Ta có;

x+2x+3x+4x+...+9x=1000-100

=>x+2x+3x+4x+...+9x=900

=>(1+2+3+4+....+9)x=900

=>45x=900

x=900:45=20

x + 2x +3x + ... + 9x = 459 - 3^2

x + 2x + 3x + ... + 9x = 459 - 9

x + 2x + 3x + ... + 9x = 450 .

x . ( 1 +2 + 3 + ... + 9 ) = 450

x . 45 = 450

x = 450 : 45

x = 10