a) \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)

\(\Rightarrow x+\frac{7}{12}=\frac{5}{6}\)

\(\Rightarrow x=\frac{5}{6}-\frac{7}{12}\)

\(\Rightarrow x=\frac{1}{4}\)

b) \(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)

\(\Rightarrow\frac{13}{23}+x=\frac{29}{30}-\frac{7}{69}\)

\(\Rightarrow\frac{13}{23}+x=\frac{199}{230}\)

\(\Rightarrow x=\frac{199}{230}-\frac{13}{23}\)

\(\Rightarrow x=\frac{3}{10}\)

a)\(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)

\(x+\frac{7}{12}=\frac{5}{6}\)

\(x=\frac{5}{6}-\frac{7}{12}\)

\(x=\frac{1}{4}\)

b)\(\frac{29}{30}-\left(\frac{13}{23}+x\right)=\frac{7}{69}\)

\(\left(\frac{13}{23}+x\right)=\frac{29}{30}-\frac{7}{69}\)

\(\left(\frac{13}{23}+x\right)=\frac{199}{230}\)\(x=\frac{199}{230}-\frac{13}{23}\)

\(x=\frac{3}{10}\)

a x=1/4                                                       b x= 3/10

\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)

\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)

\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)

\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)

\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)

\(\Rightarrow-1\le x< 6\)

\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)

Bài b tương tự

bạn ơi bạn giải câu b được ko. mk ko biết làm câu b

\(x\times\frac{6}{25}=\frac{15}{-13}\)

x=\(\frac{15}{-13}\div\frac{6}{25}\)

x=\(-\frac{125}{26}\)

các câu còn lại làm tương tự nha!!!

\(1.x.\frac{6}{25}=\frac{15}{-13}\\ x=\frac{15}{-13}:\frac{6}{25}\\ x=-\frac{125}{26}\)

\(2.x:\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\\ x:\frac{4}{10}=\frac{11}{45}\\ x=\frac{11}{45}.\frac{4}{10}\\ x=\frac{22}{225}\)

\(3.\frac{3}{8}-\frac{1}{6}.x=\frac{1}{4}\\ \frac{1}{6}.x=\frac{3}{8}-\frac{1}{4}\\ \frac{1}{6}.x=\frac{1}{8}\\ x=\frac{1}{8}:\frac{1}{6}\\ x=\frac{3}{4}\)

\(4.\frac{1}{3}+\frac{1}{2}:x=-4\\ \frac{1}{2}:x=-4-\frac{1}{3}=-\frac{13}{3}\\ x=\frac{1}{2}:\left(-\frac{13}{3}\right)=-\frac{3}{26}\)

\(5.x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}=\frac{5}{6}\\ x=\frac{5}{6}-\frac{7}{12}\\ x=\frac{1}{4}\)

mk muốn xem bài của mk đúng hay sai thôi !

chứ làm thì mk làm xong rồi !

thank you bạn nha!

Bài 1: Tìm x biết:

1) x +\(\frac{7}{12}\)= \(\frac{17}{18}\)- \(\frac{1}{9}\)                                                                               2) \(\frac{29}{30}\)- (\(\frac{13}{23}\)+ x) = \(\frac{7}{69}\)

 x +\(\frac{7}{12}\)= \(\frac{15}{18}\)                                                                                                                \(\frac{13}{23}\)+ x = \(\frac{29}{30}\)- \(\frac{7}{69}\)

             x = \(\frac{15}{18}\)- \(\frac{7}{12}\)                                                                                                    \(\frac{13}{23}\)+ x = \(\frac{199}{230}\)

             x = \(\frac{1}{4}\)                                                                                                                                   x = \(\frac{3}{10}\)

\(x=\frac{903}{391}\)

Bài này sử dụng MTCT đó bạn!

903/391 mình nghĩ vậy