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Ta có: \(A=\frac{432143214321}{999999999999}=\frac{4321\times100010001}{9999\times100010001}=\frac{4321}{9999}< \frac{1}{2}\)
\(B=\frac{1212+1212+1212+1212}{1919+1919+1919+1919}=\frac{1212\times4}{1919\times4}=\frac{1212}{1919}=\frac{12\times101}{19\times101}=\frac{12}{19}>\frac{1}{2}\)
Do:\(A< \frac{1}{2}< B\Rightarrow A< B\)
\(\frac{121212+12121212-1212}{363636+36363636-3636}\)
\(=\frac{12.10101+12.1010101-12.101}{36.10101+36.1010101-36.101}\)
\(=\frac{12\left(10101+1010101-101\right)}{36\left(10101+1010101-101\right)}\)
\(=\frac{12}{12.3}\)
\(=\frac{1}{3}\)
Ta có: \(\frac{121212+12121212-1212}{363636+36363636-3636}\)
=\(\frac{12\times\left(10101+1010101-101\right)}{36\times\left(10101+1010101-101\right)}\)
=\(\frac{12}{36}\)
=\(\frac{1}{3}\)
\(\dfrac{121212}{131313}=\dfrac{121212:10101}{131313:10101}=\dfrac{12}{13}=1-\dfrac{1}{13}\)
\(\dfrac{1313}{1414}=\dfrac{1313:101}{1414:101}=\dfrac{13}{14}=1-\dfrac{1}{14}\)
Vì \(\dfrac{1}{13}>\dfrac{1}{14}\) nên \(\dfrac{12}{13}< \dfrac{13}{14}\) hay \(\dfrac{1212}{1313}< \dfrac{1313}{1414}\)
b) \(\dfrac{1717}{2525}=\dfrac{1717:101}{2525:101}=\dfrac{17}{25}=\dfrac{51}{75}\)
\(\dfrac{515151}{727272}=\dfrac{515151:10101}{727272:10101}=\dfrac{51}{72}\)
Vì \(\dfrac{51}{75}< \dfrac{51}{72}\) nên \(\dfrac{17}{25}< \dfrac{51}{72}\) hay \(\dfrac{1717}{2525}< \dfrac{515151}{727272}\)
a) \(\dfrac{1212}{1313}=\dfrac{101x12}{101x13}=\dfrac{12}{13}< \dfrac{12+1}{13+1}=\dfrac{13}{14}\)
\(\dfrac{1313}{1414}=\dfrac{101x13}{101x14}=\dfrac{13}{14}\)
Vậy \(\dfrac{1212}{1313}< \dfrac{1313}{1414}\)
Làm tương tự câu b
1919/1212 + 51515151/36363636 = 3.
Ai tk cho mình mình tk lại.
\(\frac{1919}{1212}+\frac{515151}{363636}=3\)
HOK TỐT
\(\frac{1919}{1212}+\frac{515151}{363636}\)
\(=\frac{19}{12}+\frac{17}{12}\)
\(=\frac{36}{12}\)
\(=3\)