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135*57+135*86-35*143= 135 (57+86)-35*143=135*143-35*143=143 (135-35)=143*100=14300

91*47+49*53-18*47+24*53=(91*47-18*47)+(49*53+24*53)=47*(91-18)+53*(49+24)=47*73+53*73=73*(47+53)=73*100=7300

45-58+(-45)+(+58)-3=45-58-45+58-3=(45-45)+(58-58)-3=-3

(-57)-(-12)+3-(-57)=-57+12+3+57=(-57+57)+12+3=15

-(-24)-(-30)+(-24)-30+8=24+30-24-30+8=(24-24)+(30-30)+8=8

-(-12)+(+19)-(+12)+8-19=12+19-12+8-19=(12-12)+(19-19)+8=8

47-(-53)+(-47)-(+53)=47+53-47-53=(47-47)+(53-53)=0

-(+28)+32-(-28)+(-34)=-28+32+28-34=(-28+28)-(34-32)=-2

15-(+72)+(-15)+(+72)=15-72-15+72=(15-15)+(72-72)=0

20-(+46)+(-25)-(-46)=20-46-25+46=(20-25)+(46-46)=-5

28-(-32)+(-28)-32+5=28+32-28-32+5=(28-28)+(32-32)+5=5

-75+(-49)+(+75)+49-12=-75-49+75+49-12=(-75+75)+(49-49)-12=-12

\(...=45-58-45+58-3=-3\)

\(...=-57+12+3+57=15\)

\(...=24+30-24-30+8=8\)

\(...=12+19-12+8-19=8\)

\(...=47+53-47-53=0\)

\(...=-28+32+28-34=-2\)

\(...=15-72-15+72=0\)

\(...=20-46-25+46=-5\)

\(=...28+32-28-32+5=5\)

\(...=-75-49+75+49-12=-12\)

Bài 1: 

1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)

\(=-12-18\)

=-30

2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)

\(=36-2020+2019-136-27\)

\(=1-100-27\)

\(=-126\)

3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)

\(=144-97-244+197\)

\(=-100+100=0\)

4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)

\(=-24\cdot13+24\cdot3\)

\(=24\cdot\left(-13+3\right)\)

\(=24\cdot\left(-10\right)=-240\)

5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)

\(=54+55+56+57+58-64-65-66-67-68\)

\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)

\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)

=-50

6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)

\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)

\(=-24\cdot5+16\cdot5\)

\(=5\cdot\left(-24+16\right)\)

\(=-5\cdot8=-40\)

7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)

\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)

\(=47\cdot50-23\cdot50\)

\(=50\cdot\left(47-23\right)\)

\(=50\cdot24=1200\)

8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)

\(=-31\cdot\left(47+52+1\right)\)

\(=-31\cdot100=-3100\)

Bài 2: 

1) Ta có: \(-17-\left(2x-5\right)=-6\)

\(\Leftrightarrow-17-2x+5+6=0\)

\(\Leftrightarrow-2x-6=0\)

\(\Leftrightarrow-2x=6\)

hay x=-3

Vậy: x=-3

2) Ta có: \(10-2\left(4-3x\right)=-4\)

\(\Leftrightarrow10-8+6x+4=0\)

\(\Leftrightarrow6x+6=0\)

\(\Leftrightarrow6x=-6\)

hay x=-1

Vậy: x=-1

3) Ta có: \(-12+3\left(-x+7\right)=-18\)

\(\Leftrightarrow-12-3x+21+18=0\)

\(\Leftrightarrow-3x+27=0\)

\(\Leftrightarrow-3x=-27\)

hay x=9

Vậy: x=9

4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)

\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)

\(\Leftrightarrow-2x-3=-3\)

\(\Leftrightarrow-2x=0\)

hay x=0

Vậy: x=0

5) Ta có: x(x+3)=0

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-3\right\}\)

6) Ta có: (x-2)(x+4)=0

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)

Vậy: \(x\in\left\{2;-4\right\}\)

7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-1;3\right\}\)

Bài 1: 

1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)

=−12−18=−12−18

=-30

2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27

=36−2020+2019−136−27=36−2020+2019−136−27

=1−100−27=1−100−27

=−126

Tớ chcs cậu học thật giỏi nha !

a) (-30) + 17 + (-70) + 33

=[-30+(-70)]+(17+33)

=-100+50

=-50

b) 56 - 15 - 6 + (-75)

=(56-6)-[15+(-75)]

=50-(-60)

=110

c) (157 - 56) - (44 + 57)

=157-56-44+57

=(-157-57)-(56+44)

=-100-100

=-200

d) (-24 + 174) - (174 - 24)

=-24+174-174+24

=(-24+24)+(174-174)

=0+0

=0

e) (35 - 47) - (-123 + 35) + [20 - (123 - 57)]

=35-47+123-35+[20-123+57]

=35-47+123-35+20-123+57

=(35-35)+(123-123)+(-47+57)

=0+0+(-10)

=-10

Bn sai ở câu e dòng 4

a) 

9 8 − 4 7 + − 1 8 + 11 7 = 9 8 + − 1 8 + − 4 7 + 11 7 = 1 + 1 = 2

b)

− 5 7 ⋅ 3 11 + − 5 7 ⋅ 8 11 + 5 7 = − 5 7 3 11 + 8 11 − 1 = − 5 7 .0 = 0

\(a,\left(13+150+47\right)-\left(13+47\right)\)

\(=13+150+47-13-47\)

\(=\left[13+\left(-13\right)\right]+\left[47+\left(-47\right)\right]+150\)

\(=0+0+150\)

\(=150\)

\(b,\left(-237\right)-\left[\left(-237+155\right)-55\right]\)

\(=\left(-237\right)+237+155-55\)

\(=0+100\)

\(=100\)

\(c,57.\left(62-43\right)-62.\left(57-43\right)\)

\(=57.62-57.43-62.57+62.43\)

\(=-57.43+62.43\)

\(=43.\left(-57+62\right)\)

\(=43.5\)

\(=215\)

a , ( 13 + 150 + 47 ) - ( 13 + 47 )

= 12 + 150 + 47 - 13 - 47

= [ 12 + ( - 13 ) ] + [ 47 + ( - 47 ) ] + 150

= - 1 + 0 + 150

= 149

b , ( - 237 ) - [ ( - 237 + 155 ) - 55 ]

= - 237 - [ - 237 + 155 - 55 ]

= - 237 + 237 - 155 + 55

= [ ( - 237 ) + 237 ] + [ ( - 155 ) + 55 ]

= 0 +  ( - 100 )

= - 100

c , 57 . ( 62 - 43 ) - 62 . ( 57 - 43 )

= 57 . 62 - 57 . 43 - 62 . 57 - 62 . 43

= [ 57 . 62 - 62 . 57 ] . [ 62 . 43 - 62 . 43 ]

= 0 . 0 

= 0

a) 320 x 63 - 16 x 20 + 32 x 370

= 320 x 63 - 320 x + 320 x 37

= 320 x ( 63 - 1 + 37 )

= 320 x 99 

= 320 x ( 100 - 1 )

= 320 x 100 - 320

= 32000 - 320 = 31 680

b) 35 x 61 + 215 x 5 + 35 x 39 + 57 x 25

= 5 x 427 + 5 x 215 + 5 x 273 + 5 x 285

= 5 x ( 427 + 215 + 273 + 285 ) 

= 5 x 1200 = 6000

c) 34 x 24 - 94 x 6 + 83 x 48 - 47 x 88

= 204 x 4 - 4 x 141 + 996 x 4 - 1034 x 4

= 4 x ( 204 - 141 + 996 - 1034 )

= 4 x 25 = 100

a ) 4 7 + 2 7 + 1 7 + 3 4 + 5 4 = 3 b ) − 5 7 + − 2 7 + − 1 5 + 3 4 + 1 4 = − 1 5

c ) 5 13 + 8 13 + − 5 7 + − 20 41 + − 21 41 = − 5 7 d ) 1 28 + 3 28 + 3 14 + − 1 14 + − 1 7 = 1 7 e ) 1 2 + − 1 2 + − 2 3 + 2 3 + 3 4 + − 3 4 + − 4 5 + 4 5 + 5 6 + − 5 6 = 0