\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2023}\right)\\ =\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2022}{2023}\\ =\dfrac{1}{2023}\)

đáp án B bạn nha 

\(\dfrac{2022\times2023-1}{2023\times2021+2022}\)

= \(\dfrac{\left(2021+1\right)\times2023-1}{2023\times2021+2022}\)

= \(\dfrac{2023\times2021+2023-1}{2023\times2021+2022}\)

= \(\dfrac{2023\times2021+2022}{2023\times2021+2022}\)

= 1

$\genfrac{}{}{0ex}{}{2022\times 2023-1}{2023\times 2021+2022}$

= $\genfrac{}{}{0ex}{}{\left(2021+1\right)\times 2023-1}{2023\times 2021+2022}$

= $\genfrac{}{}{0ex}{}{2023\times 2021+2023-1}{2023\times 2021+2022}$

= $\genfrac{}{}{0ex}{}{2023\times 2021+2022}{2023\times 2021+2022}$

= 1

\(...=1+1+...+1+1\)

Số số 1 là :

\(\left(2022-2\right):2+1+1=1012\left(số\right)\)

Vậy kết quả là \(1x1012=1012\)

Số số 1 là :

$\left(2022-2\right):2+1+1=1012\left(số\acute{\hat{o}}\right)$

Vậy kết quả là $1x1012=1012$

\(a)\dfrac{7}{8}=\dfrac{7\times9}{8\times9}=\dfrac{63}{72}\)

\(\dfrac{3}{9}=\dfrac{3\times8}{9\times8}=\dfrac{24}{72}\)

Do : \(\dfrac{63}{72}>\dfrac{24}{72}\) nên \(\dfrac{7}{8}>\dfrac{3}{9}\)

Không thì bạn có thể rút gọn 3/9 đi làm cho nó gọn ạ.

\(b)\) Ta thấy : \(\dfrac{2023}{2021}>1\) ( vì tử lớn hơn mẫu )

                   \(\dfrac{2021}{2022}< 1\) ( vì tử bé hơn mẫu )

Do đó : \(\dfrac{2023}{2021}>\dfrac{2021}{2022}\)

\(c)\dfrac{5}{6}=\dfrac{5\times7}{6\times7}=\dfrac{35}{42}\)

\(\dfrac{6}{7}=\dfrac{6\times6}{7\times6}=\dfrac{36}{42}\)

Do : \(\dfrac{36}{42}>\dfrac{35}{42}\)  nên \(\dfrac{6}{7}>\dfrac{5}{6}\)

không câu SP nhé

\(A=\left(2023+1\right)\times2023:2\\ =2047276\)

(1/2 +1/3+1/4+...1/2022)x(5/6 -1/3:2/5)

=(1/2 +1/3+1/4+...1/2022)x 0

=       0

Tham khảo:

(1/2 +1/3+1/4+...1/2022)x(5/6 -1/3:2/5)

=(1/2 +1/3+1/4+...1/2022)x 0

=       0

`2022+2022:1/3+2022+2022:1/5`

`=2022+2022xx3+2022+2022xx5`

`=2022xx(1+3+1+5)`

`=2022xx10=20220`

20220

nếu các bạn trả lời phép tính của mình thì mong các vạn ghi tất cả các bước làm và phép tính ra ạ ><

`25/7 - 2 +3/2`

`= 25/7 - 14/7 +3/2`

`= 11/7 +3/2`

`= 22/14 + 21/14`

`= 43/14`

__

`4/5 xx 10/3 : 8`

`= 4/5 xx 10/3 xx 1/8`

`= 40/15 xx 1/8`

`= 8/3 xx 1/8`

`= 8/24`

`=1/3`

__

`7/3 + 2/5 :1/6`

`= 7/3 +2/5 xx 6`

`= 7/3 + 12/5`

`= 35/15 + 36/15`

`= 71/15`

1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)

\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)

=0

2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)

\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)

\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)

3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)

\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)

\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)

\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)

\(=\dfrac{52546}{15}\)

4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)

\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)

\(=\dfrac{4}{7}\)

cảm ơn nhé

\(\dfrac{2}{5}+\dfrac{1}{4}=\dfrac{8}{20}+\dfrac{5}{20}=\dfrac{13}{20}\)
\(\dfrac{1}{3}+\dfrac{3}{5}=\dfrac{5}{15}+\dfrac{9}{15}=\dfrac{14}{15}\)
\(\dfrac{1}{2}+\dfrac{1}{4}=\dfrac{2}{4}+\dfrac{1}{4}=\dfrac{3}{4}\)
\(\dfrac{1}{8}+\dfrac{5}{6}=\dfrac{3}{24}+\dfrac{20}{24}=\dfrac{23}{24}\)

ĐÂSDWADAS