a)\(3^2.9^3=9.9^3=9^{1+3}=9^4\)

b)\(2^2.5^2=4.25=100=10^2\)

c)\(8^5.2^3=8^5.8=8^{5+1}=8^6\)

d)\(9^8:3^2=9^8:9=9^{8-1}=9^7\)

a)81 mũ 3

b)10 mũ 2

c)64 mũ  5

d)9 mũ 7

k cho mk nhé

ko co x vi 3 mu x ko bang 0

`3^{x} + 4^{2} = 19^{6} : 19^{3} . 19^{2} - 3 . 1^{2015}`
`<=>3^{x} + 4^{2} = 19^{6} : 19^{5} - 3 . 1`
`<=>3^{x} + 16 = 19 - 3`
`<=>3^{x} + 16 = 16`
`<=>3^{x} = 16 - 16`
`<=>3^{x} = 0`
`=>x \in \emptyset`

\(\left(x^2+5\right)\left(x-5\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x^2+5=0\\x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x^2=-5\\x=5\end{cases}\Leftrightarrow}\orbr{\begin{cases}x\in\varnothing\\x=5\end{cases}}}\)

Vậy x=5

TK MK ĐÊ RỒI MK LÀM TIẾP!

\(x-\frac{1}{9}=\frac{8}{3}\)

\(\Leftrightarrow x=\frac{8}{3}+\frac{1}{9}\)

\(\Leftrightarrow x=\frac{24+1}{9}=\frac{25}{9}\)

(x-1)^2=25 <=> (x-1)^2=5^2 <=>x-1=5 <=> x=6

giải ra luôn đó nha

*= x²- 1²=5²

=>x - 1 = 5

=> x = 5 + 1 =6

5mũx .[1+2+1]=31.125

5mũx .8=3875

5mũx =3875:8

5 mũ x=

A.M = {x ∈ N / x ≤ 5}

A

2^{x + 3} + 2^{x + 1} = 2^x.2³ + 2^x.2 = 2^x.(2³ + 2) = 2^x.10 = 320 => 2^x = 320 : 10 = 32 = 2⁵ => x = 5

1)5^x+1 + 6.5^x+1 = 875

   5^x+1 ( 1+6 ) = 875

   5^x+1 . 7 = 875

5^x+1 = 875 : 7

5^x+1 = 125

5^x+1 = 5³

x+1 = 3

x = 3 - 1

x = 2

2)3^x+1 + 3^x+3 = 810

  3^x . 3 + 3² . 3^x+1 = 810

  3^x . 3 + 9 . 3^x . 3 = 810

  3^x .3 ( 1 + 9 ) = 810

  3^x+1 . 10 = 810

  3^x+1 = 810 : 10

  3^x+1 = 81

  3^x+1 = 3⁴ 

x+1 = 4

x = 4-1

x = 3