bao giờ vào nhà tao tao chỉ cho

Bài 1 :

\(M=\dfrac{30-2^{20}}{2^{18}}=\dfrac{2.15-2^{20}}{2^{18}}=\dfrac{15}{2^{17}}-2^2=\dfrac{15}{2^{17}}-4< 0\left(\dfrac{15}{2^{17}}< 1\right)\)

\(N=\dfrac{3^5}{1^{2021}+2^3}=\dfrac{3^5}{9}=\dfrac{3^5}{3^2}=3^3=27\)

\(\Rightarrow M< N\)

Bài 3 :

a) \(t^2+5t-8\) khi \(t=2\)

\(=5^2+2.5-8\)

\(=25+10-8\)

\(=27\)

b) \(\left(a+b\right)^2-\left(b-a\right)^3+2021\left(1\right)\)

\(\left\{{}\begin{matrix}a=5\\b=a+1=6\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}a+b=11\\b-a=1\end{matrix}\right.\)

\(\left(1\right)=11^2-1^3+2021=121-1+2021=2141\)

c) \(x^3-3x^2y+3xy^2-y^3=\left(x-y\right)^3\left(1\right)\)

\(\left\{{}\begin{matrix}x=3\\y=2\end{matrix}\right.\) \(\Rightarrow x-y=1\)

\(\left(1\right)=1^3=1\)

Ta có: ( Sửa đề )

\(A=4+4^2+4^3+...+4^{2021}+4^{2022}\)

\(A=\left(4+4^2\right)+\left(4^3+4^4\right)+...+\left(4^{2021}+4^{2022}\right)\)

\(A=20+4^2.\left(4+4^2\right)+...+4^{2020}.\left(4+4^2\right)\)

\(A=20+4^2.20+...+4^{2020}.20\)

\(A=20.\left(1+4^2+...+4^{2020}\right)\)

Vì \(20⋮20\) nên \(20.\left(1+4^2+...+4^{2020}\right)\)

Vậy \(A⋮20\)

\(#WendyDang\)

A=2+2²+2³+...+2¹⁰

2A=2²+2³+2⁴+...+2¹¹

2A-A=(2²+2³+2⁴+...+2¹¹)-(2+2²+2³+...+2¹⁰)

A=2¹¹-2

=>A+2=2¹¹

a) 3⁸ : 3⁴ + 2² x 2³ =  113

b) 3 x 4² - 2 . 3 = 42

c) 4⁶ . 3⁴ . 9⁵ : 6¹² = 9

d) 21² . 14 . 125 : 35³ . 6 = 108

e) 45³ . 20⁴ .18² : 180⁵ = 25

#BạcHà#

bn ơi ghi cả cách làm nữa bn 

ai lm lun cách làm mk sẽ k cho 2 k lun

a,( 3⁹³+3⁹⁰) : (3¹⁷. 3⁷³)

= (3³+1). 3⁹⁰ : 3⁹⁰

= 3³+1

=27+1

=28

b,(5⁵⁶+5⁷) : (5⁴⁹+1)

=5⁷. (5⁴⁹+1) : (5⁴⁹+1)

=5⁷= 78125

c,(7²²+7²¹+7²⁰) ; (2⁵+2⁴+3²)

= 7²⁰. (7²+7¹+1) : [2⁴. (2+1)+3² ]

= 7²⁰. 57 : [ 2⁴. 3 +3² ]

= 7²⁰. 57 :  ( 2⁴+3) . 3

= 7²⁰. 57 :  19 . 3

= 7²⁰. 57 : 57

= 7²⁰

Bài 2: 

a: Ta có: \(M=\left(x+y\right)^3+2x^2+4xy+2y^2\)

\(=\left(x+y\right)^3+2\cdot\left(x+y\right)^2\)

\(=7^3+2\cdot7^2=441\)

Bài 1: 

a) 0²⁰⁰² < 0²⁰²³

b) 2022⁰ = 2023⁰

c) 54⁹ < 55¹⁰

d) ( 4 + 5 )³ > 4² + 5²

đ) 9² - 3² > ( 9 - 3 )²

Bài 2:

a) 3² x 4³ - 3² + 333

= 9 x 64 - 9 + 333

= 576 - 9 + 333

= 567 + 333

= 900

b) 5 x 4³ + 24 x 5 + 41⁰

= 5 x 64 + 24 x 5 + 1

= 5 x ( 64 + 24 ) + 1

= 5 x 88 + 1

= 440 + 1

= 441

c) 2³ x 4² + 3² x 5 - 40 x 1²⁰²³

= 8 x 16 + 9 x 5 - 40 x 1

= 128 + 45 - 40

= 133

Bài 1 :

a) \(0^{2002}=0;0^{2023}=0\Rightarrow0^{2002}=0^{2023}\)

b) \(2022^0=1;2023^0=1\Rightarrow2022^0=2023^0\)

c) \(54^9< 55^9;55^9< 55^{10}\Rightarrow54^9< 55^{10}\)

d) \(\left(4+5\right)^3>\left(4+5\right)^2;\left(4+5\right)^2>4^2+5^2\Rightarrow\left(4+5\right)^3>4^2+5^2\)

đ) \(9^2-3^2=81-9=82;\left(9-3\right)^2=6^2=36\Rightarrow9^2-3^2>\left(9-3\right)^2\)

bằng 2¹⁰¹ + 2 trên 3

a)1

b)0