=>1000x=12000

hay x=12

x×125 + x×876 - x=12000

x × (125 + 876 - 1)=12000

x × 1000=12000

x=12000 : 1000

x=12

Vậy x=12

=>1000x=12000

hay x=12

χ x (125+873-1)=12000

χ  x 1000=12000

x=12000:1000

x=12

\(y\times125+y\times876-y=12000\)

\(=>y\times\left(125+876-1\right)=12000\)

\(=>y\times1000=12000\)

\(=>y=12000:1000\)

\(=>y=12\)

\(#Wendy.Dang\)

cảm ơn nha

Xx125+Xx876-X=12000 
Xx125+Xx876-Xx1=12000 
Xx(125+876-1)=12000 
Xx(1001-1)=12000 
Xx1000=12000 
X =12000:1000 
X=12

k cho mình nha!

\(125x+876x-x=12000\)

\(\Leftrightarrow125x+876x-1x=12000\)

\(\Leftrightarrow x\left(125+876-1\right)=12000\)

\(\Leftrightarrow1000x=12000\)

\(\Leftrightarrow x=12000\div1000\)

\(\Leftrightarrow x=12\)

\(\text{Vậy }x=12\)

4057+(X:38) = 20395

             X:38 = 20395-4057 

             X:38= 16338

                  X=16338 x 38

                  X= 620844

=>6000x=12000

hay x=2

125.(-6).x.(-8)=12000

125.[(-6).(-8)].x=12000

145.48.x=12000

6000.x=12000

x=12000:6000

x=2

x * 2 + x * 3 + x * 4 + x = 2130

x * (2 + 3 + 4 + 1) = 2130

x * 10 = 2130

x = 2130 : 10 = 213

2x + 3x + 4x + x = 2130

10x = 2130

x = 2130 ÷ 10

x = 213

\(\Leftrightarrow x^3+2x^2-3x-x^3-3x^2=-4\)

\(\Leftrightarrow x^2+3x-4=0\)

=>(x+4)(x-1)=0

=>x=-4 hoặc x=1

\(x\times4+x\times2+x\times10+x+x\times100=23,4\)

\(x\times\left(4+2+10+100\right)=23,4\\ x\times116=23,4\\ x=\dfrac{23,4}{116}\approx0,2\)