sossososo

:)))

Ta có \(B=5^{2024}+5^{2023}+5^{2022}\)

\(B=5^{2022}\left(5^2+5+1\right)\)

\(B=31.5^{2022}⋮31\)

Vậy \(B⋮31\) (đpcm)

Áp dụng tính chất của dãy tỉ số bằng nhau,ta có:
\(\dfrac{x}{y}=\dfrac{y}{z}=\dfrac{z}{x}=\dfrac{x+y+z}{y+z+x}=\dfrac{x+y+z}{x+y+z}=1\)
\(\Rightarrow\left\{{}\begin{matrix}x=y\\y=z\\z=x\end{matrix}\right.\)
Do đó \(\left\{{}\begin{matrix}x-y=0\\y-z=0\\z-x=0\end{matrix}\right.\)
Thay vào biểu thức \(P=\left(x-y\right)^{2022}+\left(y-z\right)^{2023}+\left(x-z-1\right)^{202}\),ta có:
\(P=0^{2022}+0^{2023}+\left(-1\right)^{202}\)
\(=0+0+1\)
\(=1\)

giup mik nhiều quá hihi

\(S=1+3^2+3^4+...+3^{2022}\)

\(3^2S=9S=3^2+3^4+3^6+...+3^{2024}\)

\(S=\dfrac{9S-S}{8}=\left(3^{2024}-1\right):8\)

d, không đáp án nào đúng

Lời giải:

$S=1+3^2+3^4+....+3^{2022}$

$9S=3^2S=3^2+3^4+3^6+...+3^{2024}$

$\Rightarrow 9S-S=3^{2024}-1$

$\Rightarrow S=\frac{3^{2024}-1}{8}$

Đáp án D.

\(A=7^{2024}-7^{2023}+7^{2022}-7^{2021}+...+7^2-7\)

=>\(7A=7^{2025}-7^{2024}+7^{2023}-7^{2022}+...+7^3-7^2\)

=>\(7A+A=7^{2025}-7^{2024}+7^{2023}-7^{2022}+...+7^3-7^2+7^{2024}-7^{2023}+...+7^2-7\)

=>\(8A=7^{2025}-7\)

=>\(A=\dfrac{7^{2025}-7}{8}\)

Bài 9,

6²x73+36x3³=36x73+36x27=36(73+27)=36x100=3600.

197-\([\)6x(5-1)²+2022⁰\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.

Bài 10,

21-4x=13

=>4x=21-13=8

=>x=8:4=2.

30:(x-3)+1=4⁵:4³=4²=16

=>30:(x-3)=16-1=15

=>x-3=30:15=2

=>x=2+3=5.

(x-1)³+5x6=38

=>(x-1)³+30=38

=>(x-1)³=38-30=8=2³

=>x-1=2

=>x=3.

Bài 1: 

a) 0²⁰⁰² < 0²⁰²³

b) 2022⁰ = 2023⁰

c) 54⁹ < 55¹⁰

d) ( 4 + 5 )³ > 4² + 5²

đ) 9² - 3² > ( 9 - 3 )²

Bài 2:

a) 3² x 4³ - 3² + 333

= 9 x 64 - 9 + 333

= 576 - 9 + 333

= 567 + 333

= 900

b) 5 x 4³ + 24 x 5 + 41⁰

= 5 x 64 + 24 x 5 + 1

= 5 x ( 64 + 24 ) + 1

= 5 x 88 + 1

= 440 + 1

= 441

c) 2³ x 4² + 3² x 5 - 40 x 1²⁰²³

= 8 x 16 + 9 x 5 - 40 x 1

= 128 + 45 - 40

= 133

Bài 1 :

a) \(0^{2002}=0;0^{2023}=0\Rightarrow0^{2002}=0^{2023}\)

b) \(2022^0=1;2023^0=1\Rightarrow2022^0=2023^0\)

c) \(54^9< 55^9;55^9< 55^{10}\Rightarrow54^9< 55^{10}\)

d) \(\left(4+5\right)^3>\left(4+5\right)^2;\left(4+5\right)^2>4^2+5^2\Rightarrow\left(4+5\right)^3>4^2+5^2\)

đ) \(9^2-3^2=81-9=82;\left(9-3\right)^2=6^2=36\Rightarrow9^2-3^2>\left(9-3\right)^2\)

\(5^{12}:5^{10}-160:10+2024^0\)
\(=5^2-16+1\)
\(=25-16+1\)
\(=10\)

Cộng vs 2024⁰ mà bạn ơi

a)\(27.65+27.35+300=27.\left(65+35\right)+300\)

\(=27.100+300=2700+300=3000\)

b)\(3838:\left[\left(190-6.5^2\right):4+3\right]\)

\(=3838:\left[\left(190-6.25\right):4+3\right]\)

\(=3838:\left[\left(190-150\right):4+3\right]\)

\(=3838:\left[40:4+3\right]=3838:\left[10+3\right]\)

\(=3838:13=\dfrac{3838}{13}\)

c)\(2022-x=2021\)

\(x=2022-2021=1\)

d)\(26+14:\left(x-5\right)=33\)

\(14:\left(x-5\right)=33-26=7\)

\(x-5=14+7=2\)

\(x=2+5=7\)

e)đề hỏi làm j thế bạn

tôi không biết làm nhưng tính ra kết quả bằng 25