a) Đặt A =  2.11 + 2.13 + ... + 2.29

= 2.(11 + 13 + 15 + ... + 29)

Đặt B = 11 + 13 + 15 + ... + 29

Số số hạng của B:

(29 - 11) : 2 + 1 = 10 (số)

A = 2.(29 + 11) . 10 : 2

= 40.10

= 400

b) (2²⁰²² + 2²⁰²¹- 2²⁰²⁰) : (2²⁰¹⁹ . 2)

= 2²⁰²⁰.(2² + 2 - 1) : 2²⁰²⁰

= 4 + 2 - 1

= 5

Đặt \(A=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{2.11}+\frac{1}{2.15}+\frac{13}{15.4}\)

\(\frac{1}{7}.A=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

\(\frac{1}{7}.A=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(\frac{1}{7}.A=\frac{1}{2}-\frac{1}{28}\)

\(\frac{1}{7}.A=\frac{14}{28}-\frac{1}{28}=\frac{13}{28}\)

\(A=\frac{13}{28}:\frac{1}{7}=\frac{13}{28}.7=\frac{13}{4}\)

Phân số cuối chép sai đề rùi nhé!

thank you

biên soạn mới hay cũ vậy hả bạn

Biên soạn mới bạn ơi!

\(B=7\left(\frac{5}{2.1}+\frac{4}{1.11}+...+\frac{13}{15.4}\right)\)

\(B=7\left(\frac{5}{2.7}+\frac{4}{7.11}+...+\frac{13}{15.28}\right)\)

\(B=7\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{15}-\frac{1}{28}\right)\)

\(B=7\left(\frac{1}{2}-\frac{1}{28}\right)\)

\(B=7\times\frac{13}{28}\)

\(B=\frac{13}{4}\)

Ta có:

\(\frac{2^3.3^4}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)

\(\frac{2^4.5^2.11^2.7}{2^3.5^3.7^2.11}=\frac{2.11}{5.7}=\frac{22}{35}\)

THANKS

2.15*75 - 2.15 : 45.
= 645/4 - 43/900
=       72541/450.

ko

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A.\(\frac{2^3.9^2}{2^2.3^2.5}=\frac{2^2.2.\left(3^2\right)^2}{2^2.3^2.5}=\frac{2.3^2}{5}=\frac{18}{5}\)

B.\(\frac{2^4.5^5.11^2.7}{2^3.5^3.7^2.11}=\frac{2^3.2.5^3.5^2.11.11.7}{2^3.5^3.7.7.11}=\frac{2.5^2.11}{7}=\frac{61}{7}\)