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\(a)\frac{4^{17}.3^4.9^6}{6^{13}}=\frac{2^{34}.3^4.3^{12}}{2^{13}.3^{13}}=\frac{2^{21}.3^{16}}{3^{13}}=2^{21}.3^3\)
\(b)\frac{2^{16}+2^8}{2^{13}+2^5}=\frac{2^8\left(2^8+1\right)}{2^5\left(2^8+1\right)}=\frac{2^3\left(2^8+1\right)}{2^8+1}=2^3=8\)
\(a,\frac{4^{17}\times3^4\times9^6}{6^{13}}\)
\(=\frac{2^{34}\times3^4\times3^{12}}{2^{13}\times3^{13}}\)
\(=\frac{2^{34}\times3^{16}}{2^{13}\times3^{13}}\)
\(=2^{21}\times3^3\)
\(b,\frac{2^{16}+2^8}{2^{13}+2^5}\)
\(=\frac{2^8\left(2^8+2^0\right)}{2^5\left(2^8+2^0\right)}\)
\(=\frac{2^8}{2^5}\)
\(=8\)
~Study well~
a) \(198+789+502+311\)
\(=\left(198+502\right)+\left(789+311\right)\)
\(=700+1100\)
\(=1800\)
b) \(15.6.4.125.8\)
\(=\left(15.4\right).6.\left(125.8\right)\)
\(=60.6.1000\)
\(=360000\)
c) \(367+129+133+371+17\)
\(=\left(367+133\right)+\left(129+371\right)+17\)
\(=500+500+17\)
\(=1000+17\)
\(=1017\)
d) \(37.64+37.35+37\)
\(=37.\left(64+35+1\right)\)
\(=37.100\)
\(=3700\)
e) \(3.25.8+4.37.6+2.38.12\)
\(=\left(3.8\right).25+\left(4.6\right).37+\left(2.12\right).38\)
\(=24.25+24.37+24.38\)
\(=24.\left(25+37+38\right)\)
\(=24.100\)
\(=2400\)
f) \(136.48+16.272+68.20.2\)
\(=136.48+16.2.136+68.2.20\)
\(=136.48+32.136+136.20\)
\(=136.\left(48+32+20\right)\)
\(=136.100\)
\(=13600\)
g) \(1+6+11+16+...+46+51\)
Số số hạng là :
\(\left(51-1\right):5+1=11\) ( số )
Tổng là :
\(\left(1+51\right)\times11:2=286\)
Chúc bạn học tốt
1+2-3-4+5+6-7-8+...+111-112+113+114+115
=1+(2-3-4+5)+(6-7-8+9)+....................................+(110-111-112+113)+114+115
=230
a) \(...=-\dfrac{12}{46}-\dfrac{15}{21}+\dfrac{3}{7}-\dfrac{7}{23}\)
\(=-\dfrac{12}{46}-\dfrac{7}{23}-\dfrac{15}{21}+\dfrac{3}{7}\)
\(=-\dfrac{6}{23}-\dfrac{7}{23}-\dfrac{5}{7}+\dfrac{3}{7}\)
\(=-\dfrac{13}{23}-\dfrac{2}{7}\)
\(=-\dfrac{13.7}{23.7}-\dfrac{2.23}{23.7}\)
\(=-\dfrac{91}{161}-\dfrac{46}{161}=-\dfrac{137}{161}\)
b) \(...=-21+\dfrac{7}{9}-\dfrac{3}{17}+\dfrac{25}{9}\)
\(=-21-\dfrac{3}{17}+\dfrac{7}{9}+\dfrac{25}{9}\)
\(=-21-\dfrac{3}{17}+\dfrac{32}{9}\)
\(=-\dfrac{3213}{153}-\dfrac{27}{153}+\dfrac{544}{153}=-\dfrac{2696}{153}\)
A = 1 + 2 + 2x2 + 2x2x2 + 2x2x2x2 + ... + 2x2x...x2 9 lần số 2
=> 2xA = 2 + 2x2 + 2x2x2 + ... + 2x2x...x2 ( 10 lần số 2)
=> 2xA - A = 2 + 2x2 + 2x2x2 + ... + 2x2x...x2 10 lần số 2 - ( 1 + 2 + 2x2 + 2x2x2 + 2x2x2x2 + ... + 2x2x...x2 9 lần số 2 )
=> A = 2x2x2x...x2 - 110 lần số 2 = 512x2 - 1 = 1024 - 1 = 1023