\(26⋮\left(x-1\right);38⋮\left(x-1\right)\Rightarrow x-1\inƯC\left(26,38\right)=\left\{\pm2;\pm1\right\}\Rightarrow x\in\left\{-1;0;2;3\right\}\)

Mà x là số tự nhiên \(\Rightarrow x\in\left\{0;2;3\right\}\)

d) 26 = 2 . 13

38 = 2 . 19

ƯCLN(26,38) = 2

ƯC(26,38) = Ư(2) = 1,2

Mà theo đề bài : 26 ⋮ (x-1) ; 38 ⋮ (x-1)

Nên : x = 2 hoặc 3

d)2².2^x=16

⇔4.2^x=16

⇔2^x=4

⇔2^x=2²

⇔x=2

2^x=2⁴:2²

2^x=2²

=> x=2

a) x = 2

b) x = 2

c) x = 2

d) x = 1

dái wa      

Giúp mình đi mình đang cần gấp

d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)

\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)

hay \(x=\dfrac{25}{372}\)

Vậy: \(x=\dfrac{25}{372}\)

e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)

f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)

\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)

\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)

\(\Leftrightarrow3x=\dfrac{1}{9}\)

hay \(x=\dfrac{1}{27}\)

g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)

\(\Leftrightarrow\dfrac{4}{3}x=2\)

hay \(x=\dfrac{3}{2}\)

Vậy: \(x=\dfrac{3}{2}\)

h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)

  Vậy ...

i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)

  Vậy ...

a, (x + 30) – 75 = 125

=> x + 30 = 125 + 75 = 200

=> x = 200 – 30

=> x = 170

Vậy x = 170

b, x – 72 : 36 = 18

=> x – 2 = 18

=> x = 18 + 2 = 20

Vậy x = 20

c, x – 17 = 54

=> x = 54 +17

=> x = 71.

Vậy x = 71

d, 36 – (x – 2) = 12

=> x – 2 = 36 – 12

=> x = 24 + 2 = 26

Vậy x = 26

e, 9x – 7 = 837

=>9x = 837 + 7 = 844

=> x =  844 9

Vậy x =  844 9

f, (x – 15) – 107 = 0

=> x – 15 = 107

=> x = 107 +15

=> x = 122.

Vậy x = 122

g, 134 + (116 – x) = 145

=> 116 – x = 145 – 134

=> x = 116 – 11

=> x = 5.

Vậy x = 5

a. 2x - 3 = 125 : 25
    2x - 3 = 5
    2x      = 5 + 3
   2x       = 8
     x       = 8 : 2 = 4
b. 472 : ( 24 + 5x ) + 8 = 16
              ( 24 + 5x ) + 8 = 472 : 16
              ( 24 + 5x ) + 8 = 29,5
                24 + 5x          = 29,5 - 8

                24 + 5x          = 21,5

                         5x          = 21,5 - 24

                         5x          = -2,5

                           x          = -2,5 : 5 = -0,5

a.

(2x - 3).25 =125

2x - 3       =125 : 25

2x - 3       = 5

2x            =5 + 3

2x            = 8

x             = 8 :2

x             =4

b. 

472 : (24 +5x) + 2 mủ 3 =16

472 :(24 + 5x) + 8         = 16

472 :(24 + 5x)               = 16 - 8

472 :(24 + 5x)               = 8

24 + 5x                        = 472 : 8

24 + 5x                        =59

5x                                = 59 - 24

5x                                = 35

x                                  =35:5

x                                  = 7

5x                                = 

Bài 1: 

\(101\cdot125+101\cdot25-101\cdot50\)

\(=101\cdot\left(125+25-50\right)\)

\(=101\cdot100\)

\(=10100\)

Bài 2: 

\(76\cdot115+56\cdot24+59\cdot24\)
\(=76\cdot115+24\cdot\left(56+59\right)\)

\(=76\cdot115+24\cdot115\)

\(=115\cdot\left(76+24\right)\)

\(=115\cdot100\)

\(=11500\)

còn bài 3,4,5 thì sao ak