Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a,\left(2x-16\right)^7=128\\ \Rightarrow\left(2x-16\right)^7=2^7\\ \Rightarrow2x-16=2\\ \Rightarrow2x=18\\ \Rightarrow x=9\\ b,x^3.x^2=2^8:2^3\\ \Rightarrow x^5=2^5\\ \Rightarrow x=5\\ c,3^{x-3}-3^2=2.3^2\\ \Rightarrow3^{x-3}-9=18\\ \Rightarrow3^{x-3}=27\\ \Rightarrow3^{x-3}=3^3\\ \Rightarrow x-3=3\\ \Rightarrow x=6\)
Ta có:
A=\(\frac{3^{10}.11+3^8.45}{3^9.16}\)
A=\(\frac{3^{10}.11+3^{10}.5}{3^9.16}\)
A=\(\frac{3^{10}.\left(11+5\right)}{3^9.16}\)
A=\(\frac{3^{10}.16}{3^9.16}\)
A=3
Hok tốt
\(\frac{3^{10}.11+3^8.45}{3^9.16}\)
=\(\frac{59049.11+6561.45}{19683.16}\)
=\(\frac{649539+295245}{314928}\)
=\(\frac{944784}{314928}\)
=3
\(\Rightarrow]\) K CHO MÌNH NHA!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!PLEASE
\(x^2+11x+28=0\)
\(x^2+4x+7x+28=0\)
\(x\left(x+4\right)+7\left(x+4\right)=0\)
\(\left(x+4\right)\left(x+7\right)=0\)
\(\Rightarrow\hept{\begin{cases}x+4=0\\x+7=0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x=-4\\x=-7\end{cases}}\)
Đặt \(A=\frac{1.2+2.4+3.6+4.8+5.10}{4+6.8+9.12+12.16+15.20}\)
\(\Rightarrow A=\frac{1.\left(1+2\right)+2.\left(1+2\right)+3.\left(1+2\right)+4.\left(1+2\right)+5.\left(1+2\right)}{4+2.\left(3+4\right)+3.\left(3+4\right)+4.\left(3+4\right)+5.\left(3+4\right)}\)
\(\Rightarrow A=\frac{\left(1+2+3+4+5\right).\left(1+2\right)}{4+\left(2+3+4+5\right).\left(3+4\right)}\)
\(\Rightarrow A=\frac{\left(1+5\right).5:2.\left(1+2\right)}{4+\left(2+5\right).4:2.\left(3+4\right)}\)
\(\Rightarrow A=\frac{6.5:2.3}{4+7.4:2.7}=\frac{45}{4+98}=\frac{45}{102}=\frac{15}{34}\)
Vậy \(A=\frac{15}{34}\)
Chúc bn học tốt
a) 3(x + 5) + 5(x + 7) = 58
3x + 15 + 5x + 35 = 58
8x + 50 = 58
8x = 58 - 50
8x = 8
x = 8 : 8
x = 1
b) 3(x + 7) - 2(x + 3) = 16
3x + 21 - 2x - 6 = 16
x + 15 = 16
x = 16 - 15
x = 1
115 + 3 . ( x - 2 ) = 295
3 . ( x - 2 ) = 295 - 115
3 . ( x - 2 ) = 180
x - 2 = 180 : 3
x - 2 = 60
x = 60 + 2
x = 62
16 : 2 . x = 9
x = ko tính được
20 - ( x +14 ) = 5
x + 14 = 20 - 5
x + 14 = 15
x = 15 - 14
x = 11
57 : ( 9 . x - 27 ) = 0
vì số nào chia 0 thì bằng 0 mà 27 : 9 = 3 nên
x = 3
Tìm x:
115+3.(x-2)= 295 16:2.x= 9 20-(x+14)=5 57:(9x-27)=0
3.(x-2)= 295-115 2.x= 16:9 x+14= 20-5 9x-27= 0
3.(x-2)= 180 2.x= 16/9. x+14= 15. 9x= 27
x-2= 180:3 x= \(\frac{16}{9}:2\) x= 15-14 x= 27:9
x-2= 60 \(x=\frac{16}{9}.\frac{1}{2}\) x= 1 x= 3
x= 60+2 \(x=\frac{8}{9}\)
x= 62
\(=x^2+16x+48=x^2+4x+12x+48=\left(x+4\right)\left(x+12\right)\)
=(x+4)(x+12)